CCNA Class 07: IPv4 Address Classes Subnetting

 IP Addressing & Subnetting with Detail Example Practice 

Example of Class-A (Mathematical Calculation)-

Example 01: Here, the Class A Network an IP Address 13.15.0.0/16. Find the Max Number of Subnet & Max Number of Host. List of Available IP Addresses.

Solution: Let, Class A Network Default Subnet Mask is,

Network ID	Host ID
255	0	0	0
11111111	00000000	00000000	00000000

The formula is to find the Max Number of Sub Network is 2n and Max Number of Host Networks is 2n-2.

Here, From example 01

Max Number of Sub Network, n = 8 bits

Max Number of Host per Subnet, n = 16 bits

Therefore,

The total Sub Networks are, 28 = 256 Subnet

The Total Host per Subnet is, 216-2 = 65,534 Hosts

Network ID		Host ID
255	255	0	0
11111111	11111111	00000000	00000000

Table-1(a): List of Available IP Addresses Allocations

S/N	Subnet ID	Host Addresses	Subnet Broadcast
01	13.15.0.0	13.15.0.1 - 13.15.255.254	13.15.255.255
02	13.16.0.0	13.16.0.1 - 13.16.255.254	13.16.255.255
03	13.17.0.0	13.17.0.1 - 13.17.255.254	13.17.255.255
04	13.18.0.0	13.18.0.1 - 13.18.255.254	13.18.255.255
05	13.19.0.0	13.19.0.1 - 13.19.255.254	13.19.255.255
06	13.20.0.0	13.20.0.1 - 13.20.255.254	13.20.255.255
** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** ** **
240	13.255.0.0	13.255.0.1-13.255.255.254	13.255.255.255

Example 02: the Class A Network an IP Address 10.0.0.0/27. Find the Max Number of Subnet & Max Number of Host. List of Available IP Addresses.

Here, From example 02

Max Number of Sub Network, n = 19 bits

Max Number of Host per Subnet, n = 5 bits

Therefore,

The total Sub Networks are, 219 = 524,288 Subnet

The Total Host per Subnet is, 25-2 = 30 Hosts

Table-1(a): List of Available IP Addresses Allocations

S/N	Subnet ID	Host Addresses	Subnet Broadcast
01	10.0.0.0	10.0.0.1 - 10.0.0.30	10.0.0.31
02	10.0.0.32	10.0.0.33 - 10.0.0.62	10.0.0.63
03	10.0.0.64	10.0.0.65 - 10.0.0.94	10.0.0.95
04	10.0.0.96	10.0.0.97 - 10.0.0.126	10.0.0.127
05	10.0.0.128	10.0.0.129 - 10.0.0.158	10.0.0.159
06	10.0.0.160	10.0.0.161 - 10.0.0.190	10.0.0.191
07	10.0.0.192	10.0.0.193 - 10.0.0.222	10.0.0.223
08	10.0.0.224	10.0.0.223-10.0.0.254	10.0.0.255

Practice 01: The Class A Network an IP Address 10.10.1.0/29. Find the Max Number of Subnet & Max Number of Host. List of Available IP Addresses.

Practice 02: The Class A Network an IP Address 10.10.10.10/25. Find the Max Number of Subnet & Max Number of Host. List of Available IP Addresses.

Example of Class-B (Mathematical Calculation)-

Example 01:  the Class B Network an IP Address 135.15.0.0/16. Find the Max Number of Subnet & Max Number of Host. List of Available IP Addresses

Solution: Let the default Subnet mask of Class B Network -

Network ID		Host ID
255	255	0	0
11111111	11111111	00000000	00000000

Here, From the example 01

 Max Number of Sub Network, n = 0 bits

Max Number of Host per Subnet, n = 16 bits

Therefore,

The total Sub Networks are, 20 = 1 Subnet

The Total Host per Subnet is, 216-2 = 65,534 Hosts

Table-2(a): List of Available IP Addresses Allocations

S/N	Subnet ID	Host Addresses	Subnet Broadcast
01	135.15.0.0	135.15.0.1 - 135.15.255.254	135.15.255.255

Practice 01: The Class B Network an IP Address 172.16.1.0/27. Find the Max Number of Subnet & Max Number of Host. List of Available IP Addresses

Practice 02: The Class B Network an IP Address 135.15.1.0/29. Find the Max Number of Subnet & Max Number of Host. List of Available IP Addresses

Example of Class-C (Mathematical Calculation)-

Example 01:  The Class C Network an IP Address 200.150.10.0/26. Find the Max Number of Subnet & Max Number of Host. List of Available IP Addresses

Solution: Let the default Subnet mask of Class C Network -

Network ID			Host ID
255	255	255	0
11111111	11111111	11111111	00000000

Here, From the example 01

Max Number of Sub Network, n = 2 bits

Max Number of Host per Subnet, n = 6 bits

Therefore,

The total Sub Networks are, 22 = 4 Subnet

The Total Host per Subnet is, 26-2 = 62 Hosts

Table-2(a): List of Available IP Addresses Allocations

S/N	Subnet ID	Host Addresses	Subnet Broadcast
01	200.150.10.0	200.150.10.1 - 200.150.10.62	200.150.10.63
02	200.150.10.64	200.150.10.65 - 200.150.10.126	200.150.10.127
03	200.150.10.128	200.150.10.129 - 200.150.10.190	200.150.10.191
04	200.150.10.192	200.150.10.193 - 200.150.10.254	200.150.10.255

Practice 01: The Class C Network an IP Address 192.168.1.0/24. Find the Max Number of Subnet & Max Number of Host. List of Available IP Addresses

Practice 02: The Class C Network an IP Address 198.155.100.0/29. Find the Max Number of Subnet & Max Number of Host. List of Available IP Addresses

Home Tasks- 

• Class B subnetting Practice

• Example 01, we've been allocated a Class B network with an IP address of 135.15.0.0/16. Find the Max Subnet & Max Hosts Per sub networks and List of the Available IP Addresses.

• Example 02, we've been allocated a Class B network with an IP address of 172.16.0.0/27.  Find the Max Subnet & Max Hosts Per sub networks and List of the Available IP Addresses.

• Class C subnetting Practice 

• Example 01, The Class C network with an IP address of 192.168.10.0/24. Find the Max Subnet & Max Hosts Per sub networks and List of the Available IP Addresses.

• Example 02, The Class C network with an IP address of 192.168.100.0/29. Find the Max Subnet & Max Hosts Per sub networks and List of the Available IP Addresses.